[antlr-interest] bug in java.g?
SainTiss
saintiss at arklinux.org
Tue Feb 3 16:21:30 PST 2004
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Hi,
On Tuesday 03 February 2004 21:03, Terence Parr wrote:
> On Feb 3, 2004, at 11:55 AM, SainTiss wrote:
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> >
> > Hi,
> >
> > when parsing a file containing nothing but the following line:
> >
> > m = (TEST) d;
> >
> > I get the following exception:
> >
> > parser exception: emp.java:1:1: unexpected token: m
> > emp.java:1:1: unexpected token: m
> > at JavaRecognizer.statement(JavaRecognizer.java:2058)
> > at Main.parseFile(Main.java:81)
> > at Main.doFile(Main.java:54)
> > at Main.main(Main.java:24)
> >
> > I'm calling the "statement()" method from the JavaRecognizer, so the
> > file
> > should be valid.
> > What's more, if I add a word (e.g. "smdfjmkj") on a line after the
> > statement
> > in the file, the parser does *not* throw the exception...
> >
> > Is there an explanation for this?
>
> Howdy.
>
> Yes, statement is not a "start symbol" EOF cannot follow it normally.
> YOu must make a rule liek this:
>
> stat_entry : stat ;
That doesn't seem to solve the problem... Still the exact same exception...
>
> not called by anybody so ANTLR does the right thing. Then invoke the
> grammar from stat_entry.
>
> The second problem you have is that you told antlr to match a
> statement, not two. It ignores what it doesn't care. It did theone
> statement and returned :)
I told it to match one statement indeed, but the problem is that it does *not*
seem to ignore everything else... With this input:
m = (TEST) n;
there is one statement, but the parser crashes.
With this input:
m = (TEST) n;
tessmklj
The parser successfully parses the first statement, and does not crash... So
that does look quite odd, no?
Thanks,
Hans
>
> :)
>
> Terence
> --
> Professor Comp. Sci., University of San Francisco
> Creator, ANTLR Parser Generator, http://www.antlr.org
> Co-founder, http://www.jguru.com
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>
>
>
>
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>
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