[antlr-interest] Re: linear list from tree

[Marc]

On 8/10/05, Marc <mschellens at gmail.com> wrote:
> I would like to build a linear list made from the 'expr' which are
> spread over a tree.
> The following grammer fragment does not work.
> So how to do it?
> 
> Thanks,
> marc
> 
> output should be:
> #( ARRAYIN e1_1 e1_2 e1_3 ...)
> // _1, _2 ... loop number

Sorry, that should read iteration number.
Inspired by Bryan's reply I got it working, but a general question remains:

How to append something to the actual list, within a loop?

ie.

rule!
:  (#(A e:expr (ee:expr)?) 
)+

output should be something like:

(e1 ee1 e2 e3 ee3 e4 ...)

the numbers are again denote the interation number

Thanks,
marc


> 
> 
> arrayindex_list!
>     : ( #(ARRAYIX
>                 ( ALL
>                 | ( e1:expr // 0 or 2
>                         {
>                                       #arrayindex_list = #( NULL,
> (arrayindex_list),e1);
> // also not working:        #arrayindex_list = #( arrayindex_list,e1);
> //                                    #arrayindex_list = #(
> (arrayindex_list),e1);
> 
> 
>                         }
>                     )
>                 )
>         )+
>         {
> //            #arrayindex_list = #([ARRAYIX,"[...]"], arrayindex_list);
> //            #arrayindex_list->SetArrayIndexList( ixList.release());
>         }
>     ;
>