[antlr-interest] Simple question

[dotnet fr]

It's okay, it works very well.

Thank you a lot Robert for this fast good answer :)

2006/7/25, Hill, Robert <rhill03 at eds.com>:
> You need to get the Lexer to return 1 token containing all your
> characters (probably best calling it a "String" or "CharacterLiteral"
> perhaps ;) ) instead of the lexer returning 1 token per char and
> building a tree of those single character tokens.
>
> try
>
> >chars  :       CHAR    ;
> >option buildAST is set to true;
>
> >CHAR   :   ('a'..'z' | 'A'..'Z')+;
>
> Cheers,
> Rob
>
>
>
> --
> Rob Hill
> EDS - Hallamshire Business Park
> F1E/045
> Sheffield
> T:      +44 (0) 114 291 1928
> M:      +44 (0) 791 732 1227
> E:      rhill03 at eds.com
>
>
>
> >-----Original Message-----
> >From: antlr-interest-bounces at antlr.org
> >[mailto:antlr-interest-bounces at antlr.org] On Behalf Of dotnet fr
> >Sent: 25 July 2006 13:10
> >To: antlr-interest at antlr.org
> >Subject: [antlr-interest] Simple question
> >
> >Hi Everyone,
> >
> >I've got a simple question :
> >
> >-in the parser I have :
> >chars  :       (CHAR)+ ;
> >option buildAST is set to true;
> >
> >-in the lexer I have :
> >CHAR   :   ('a'..'z') | ('A'..'Z')    ;
> >
> >When I print the ast, my chars is not a token but a letter
> >(the first) with a lot of siblings. How to get the chars like a Token ?
> >
> >Thank you in advance
> >
> >--
> >dotnet
> >
>


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