[antlr-interest] Problem with '.' character
Bertalan Fodor (LilyPondTool)
lilypondtool at organum.hu
Wed Jan 23 08:03:02 PST 2008
Isn't it possible to write this:
var1=var2.var3=myTable.myField
With ANTLR 3, in this case I think LL(*) with backtracking should find
its way, because the '=' sign will guide it.
Bert
Daniels, Troy (US SSA) wrote:
> Why is var2.var3 not a field expression? Is it because they are on
> different lines? If so, you need to exclude newlines from your
> ignored whitespace, and write the line-based rules as something like:
>
> assignment: expr EQ expr NL;
>
> rather than what I assume your current rule is:
>
> assignment: expr EQ expr;
>
> where NL matches whatever is allowed for newlines.
>
> Troy
>
>
> ------------------------------------------------------------------------
> *From:* antlr-interest-bounces at antlr.org
> [mailto:antlr-interest-bounces at antlr.org] *On Behalf Of *Dev Team
> *Sent:* Wednesday, January 23, 2008 10:30 AM
> *To:* antlr-interest at antlr.org
> *Subject:* [antlr-interest] Problem with '.' character
>
> Hi there,
> I am currently trying to write a grammar with antlr.
> But the '.' character is used for both table/field separator and
> statement ending.
> here is an example :
>
> |method public void myMethod() :
> //...
> var1 = var2.
> var3 = myTable.myField.
> //...
> end method.
> |
> So, the problem is that the grammar considers 'var2.var3' as a
> table/field expression.
> Does someone know how to resolve this problem ?
> thanks in advance
>
--
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