[antlr-interest] C# Just starting with Parsers, Trees

[Doc In Nuke]

Hi,

Thanks for the information, however i am truly a beginner, what do I 
need to get this to work in ANTLR:

funcname : n=NAME (n+='.' n+=NAME)* (n+=':' n+=NAME)? -> ^(FUNCNAME $n+);

I added a token at the start of the grammar named FUNCNAME but i still 
have grammar errors :(
Do I need to declare n in a special way ?

(if you have a link to a documentation on the site I ll gladly take it)

Best Regards,


Gavin Lambert wrote:
> At 03:12 23/05/2008, Doc In Nuke wrote:
> >One of the rule i added for exemple is the following one:
> >globalfuncdec    :    'function' ^ funcname funcbody ;
> >
> >so for every global function (declaration not starting with local)
> >i get a subtree with the funcname and funcbody block.
> >Now what would really be nice is a way to get the funcname as 1
> >token and not more.
> >funcname is the following rule:
> > funcname : NAME ('.' NAME)* (':' NAME)? ;
>
> There's a few ways you can go here.  One is to convert funcname into a 
> lexer rule (but this may introduce problems into your grammar, if it's 
> not sufficiently unique).  Another is to keep it as separate tokens 
> but put it into a subtree, like this:
>
> funcname : n=NAME (n+='.' n+=NAME)* (n+=':' n+=NAME)? -> ^(FUNCNAME $n+);
>
> I'm not completely sure about this last option (I've never used it 
> myself), but I think you can also construct an imaginary token around 
> it after the fact.  Something like this:
>
> globalfuncdec : 'function' funcname funcbody -> ^('function' 
> FUNCNAME[$funcname.text] funcbody);
>
> I think doing this causes it to lose the line/column information 
> though; there is a way to preserve that but I'm not sure exactly how 
> in this case.
>
>