[antlr-interest] C# Just starting with Parsers, Trees

[Doc In Nuke]

Hi,

Darn, I am so stupid sometimes :)

I got around to figuring the thing with the funcname thingy but I was 
looking at a way to concatenate the stuff and was thinking of doing it 
afterwards :)

With your method it is one shot and I do not even have to recreate the 
string after from the bits :)

Thanks a lot to all of you :)

Jim Idle wrote:
> On Fri, 2008-05-23 at 17:29 +0300, Doc In Nuke wrote:
>> Hi,
>>
>> Thanks for the information, however i am truly a beginner, what do I 
>> need to get this to work in ANTLR:
>>
>> funcname : n=NAME (n+='.' n+=NAME)* (n+=':' n+=NAME)? -> ^(FUNCNAME $n+);
>>
>> I added a token at the start of the grammar named FUNCNAME but i still 
>> have grammar errors :(
>> Do I need to declare n in a special way ?
>>
>> (if you have a link to a documentation on the site I ll gladly take it)
>>     
>
> Your variables can only accumulate the same type, so you can't 
> accumulate ':' and '.' and NAME. However, it is usually more useful to 
> create nodes from the elements like ':' and '.' as this gives you a 
> tree that helps resolve them (with symbol tables and so on. Of course 
> if you are just going to 'print' them separately then you might not 
> need that, in which case you probably don't need the n+= anyway.
>
> If you want a flat token sequence in the tree, but within a FUNC node 
> then do this:
>
>
> funcname : ns=nameSequence -> ^(FUNCNAME $ns) ;
>
> nameSequence : NAME ('.' NAME)* (':' NAME)?  ;
>
> If you want a tree (I usually do this, but as i say it is more useful 
> when you are resolving name space sequences and so on, then use:
>
> nameSequence : NAME ('.'^ NAME)* (':'^ NAME)?  ;
>
> And construct the tree grammar rules appropriately
>
> funcname: ^(FUNCNAME names) ;
>
> names : ^(':' nameSeq NAME)
>       | nameSeq
>       ;
>
> nameSeq : ^('.' nameSeq nameSeq)
>         | NAME
>         ;
>
> (Check that, I just typed it straight in to the email ;-).
>
> Jim
>