[antlr-interest] LL(k) vs LALL(k) vs SLL(k) (was Nondeterminism problem)
Greg Lindholm
glindholm at yahoo.com
Fri Dec 19 14:14:52 PST 2003
Could someone post a definition and explaination of the differences of these:
LL(k) vs LALL(k) vs SLL(k)
It's been kinda hard to follow this tennis match :)
Terence Parr <parrt at cs.usfca.edu> wrote:
On Friday, December 19, 2003, at 12:09 PM, sarah2geller wrote:
> Since t is not on the right side of a production, the t production is
> not reachable in the grammar.
>
> As I said before, LL(1), SLL(1), and LALL(1) are all the same grammar
> class. This is a well-known fact that you can find in any text book.
I think you'll find it says more precisely that LL(1) can be rewritten
as SLL(1) but they are not the same class of grammars. Same class of
languages, though. :)
> So when I said the grammar above was LL(1), that means that it is
> also SLL(1) because they are the same class. Saying "strong LL(1)" is
> redundant because all LL(1) grammars are strong.
I just posted an LL(1) grammar that is not LALL(1) nor SLL(1). You
have to do the transformation I showed. The difference between same
and equivalent gets kinda murky. ;)
> LL(k) is more
> powerful than LALL(k) and SLL(k) only for k>1.
And for k=1 grammars, but not languages; just to harp on it for a
second ;)
Terence
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