[antlr-interest] java example grammar

[Monty Zukowski]

I think you got it right, Ron, though I'm not sure what your question  
really was.  It does go through that whole chain of rules to match  
IDENT in identPrimary.

Monty Zukowski

ANTLR & Java Consultant -- http://www.codetransform.com
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On Apr 23, 2004, at 4:44 PM, ronald.petty at milliman.com wrote:

>
> I was trying to use the java grammar as a bases for a VB grammar (just  
> seeing how to handle expression order etc).  The first structure I was  
> trying to figure out for the for loop.  In the java.g there is
>
> statement
>         :
>         ...
>         // For statement
>         |       "for"
>                         LPAREN!
>                                 forInit SEMI!   // initializer
>                                 forCond SEMI!   // condition test
>                                 forIter         // updater
>                         RPAREN!
>                         statement                     // statement to  
> loop over
>
>         ....
>         ;
>
> If I was using this as the input
>
> for ( i = 0; .......
>
> It would match "for" "(" then call the rule forInit.  
>
> forInit
>                 // if it looks like a declaration, it is
>         :       (       (declaration)=> declaration
>                 // otherwise it could be an expression list...
>                 |       expressionList
>                 )?
>                 {#forInit = #(#[FOR_INIT,"FOR_INIT"],#forInit);}
>         ;
>
> I noticed that "i" cannot be a declaration because of the typeSpec in  
> the declaration rule would mean it needs to "int i" or something like  
> that, so I assume "i" is an expressionList (also because i had to be  
> declared already).  So following that path lead to this
>
> expressionList ->
> expression->
> assignmentExpression->
> conditionalExpression->
> logicalOrExpression->
> logicalAndExpression->
> inclusiveOrExpression->
> exclusiveOrExpression->
> andExpression->
> equalityExpression->
> relationalExpression->  (not 100% here)  (nested question; ( subrule1  
> )* | subrule2  if you don't match subrule1 do you have to match  
> subrule2?  I think this does a zero match subrule1 here
> shiftExpression->
> additiveExpression->
> multiplicativeExpression->
> unaryExpression->
> unaryExpressionNotPlusMinus->
> postfixExpression->
> primaryExpression->
> identPrimary->
> IDENT  (Match finally)
>
> Hopefully I was right in this, if this is true, is this because
>         1) "i" is not a declaration (becuase in Java it has already  
> been declared (and if Option Explicit is on in VB this is the same as  
> having it Dim i somewhere or Public i)
>         2) "i" is really an expression becuase it is really an LValue  
> which is the output of someprevious RValue?  (I hope I am not  
> slaughtering terms here)
>         3) and becuase of 2) this means that an LValue is the simplest  
> kind of expression and that is why it is at the end of this chain  
> (meaning it is the highest on the precendence) (not sure about this)
>
> I am thinking in the right way about this?
>
> Thanks alot
> Ron
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