[antlr-interest] Solution to " How to have strings enclosed in " and/or ""

[matthew ford]

No greedy=false did no do it

It generated the test

   // nongreedy exit test
   if ((LA(1)=='"'||LA(1)=='&') && (true)) break _loop11;
but I need to match  '&' 'q' 'u' 'o' 't' ';' in order to exit not just &

lexer is

STRING
options {
    paraphrase="STRING";
}
  :STRING_PART
 (STRING_PART)*
 ;

protected
STRING_PART
 : {  ( (LA(1) == '"')
           || ( (LA(1) == '&')
              && (LA(2) == 'q')
              && (LA(3) == 'u')
              && (LA(4) == 'o')
              && (LA(5) == 't')
              && (LA(6) == ';'))
        ) }?
        ('"'
         | ('&' 'q' 'u' 'o' 't' ';')
        ) (
   options {
    generateAmbigWarnings=false;
    greedy=false;
   }
  : '\r' '\n'  {newline();}
  | '\r'   {newline();}
  | '\n'   {newline();}
  | ~('\n'|'\r')
  )*
 ('"' !
    | ('&' ! 'q' ! 'u' ! 'o' ! 't' ! ';' !)
   )
 ;

matthew

----- Original Message ----- 
From: "Terence Parr" <parrt at cs.usfca.edu>
To: <antlr-interest at yahoogroups.com>
Sent: Sunday, December 12, 2004 5:14 PM
Subject: Re: [antlr-interest] Solution to " How to have strings enclosed in
" and/or &quot;"


>
>
> On Dec 11, 2004, at 10:08 PM, matthew ford wrote:
> > This is what I came up with which seems to work
> >
> > The interesting bit is
> >   | ~('\n'|'\r')
> >         { if ( (LA(1) == '"') || ( (LA(1) == '&')
> >               && (LA(2) == 'q')
> >               && (LA(3) == 'u')
> >               && (LA(4) == 'o')
> >               && (LA(5) == 't')
> >               && (LA(6) == ';'))
> >         ) {break;} }
> > where the break; is used to break out of antlr' ( )* block
>
> Won't a greedy=false loop do the same thing?
>
> Ter
>
>
>
>
>
>
> Yahoo! Groups Links
>
>
>
>
>
>
>



 
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