A while ago, I mentioned that I do:
('\r')? '\n' { newline(); }
to match newlines. It seems to be the case that explicitly
testing for the '\r' is unnecessary: if a '\n' is required, who
cares what the character immediately before it is? So this can
simply be:
'\n' { newline(); }
and it will work on both *nix and Windows, right?
- Paul