[antlr-interest] Combining += with returns and actions
Jim Idle
jimi at temporal-wave.com
Sat Aug 11 12:08:39 PDT 2007
Try
mr1=memberReference {q.AddSelect($mr1.Reference) } (COMMA
m2=memberReference {q.AddSelect($mr2.Reference) })*
From: antlr-interest-bounces at antlr.org
[mailto:antlr-interest-bounces at antlr.org] On Behalf Of Ayende Rahien
Sent: Friday, August 10, 2007 8:04 PM
To: antlr-interest at antlr.org
Subject: [antlr-interest] Combining += with returns and actions
I have run into a snag when building a dialect with ANTLR 3, I have the
following:
selectClause[Query q]
: SELECT
mr+=memberReference (COMMA mr+=memberReference)*
{
q.AddSelection ($mr);
}
;
Where memberReference is defined as:
memberReference returns[MemberReferenceExpression Reference]
: ids+=IDENTIFIER (DOT ids+=IDENTIFIER)?
{
$Reference = new MemberReferenceExpression();
foreach(IToken token in $ids)
{
$Reference.AddReference(token.Text);
}
};
My problem is that I would like to get a list of
MemberReferenceExpression, but what I end up getting is a list of tree.
The problem is here:
PushFollow(FOLLOW_memberReference_in_selectClause76);
mr = memberReference();
followingStackPointer_--;
adaptor.AddChild(root_0, mr.Tree);
if (list_mr == null) list_mr = new ArrayList();
list_mr.Add(mr.Tree); // <-- I want to get mr.Reference, not mr.Tree
Any idea how to solve that?
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