[antlr-interest] embedding Java codes to grammar problem

[Panayiotis]

Fırat KÜÇÜK wrote:
> what about "while statement" situation?
>
> 2007/6/4, Panayiotis <panayk at gmail.com>:
>> I'm not sure I understand what you want to do, but would the 
>> following work?
>>
>> sample_rule
>>     :    SOME_TOKEN bla_bla_rule ({1 == 1}? another_rule)?
>>     ;
>>
>> This will parse 'SOME_TOKEN' followed by 'bla_bla_rule' and then,
>> depending on the truth value of the semantic predicate '1 == 1', it will
>> try to parse an optional 'another_rule'.
>> A related syntax is {1 == 1}?=>.
>>
>> Panayiotis
>>
>> Fırat KÜÇÜK wrote:
>> > any solution?
>> >
>> > 2007/6/1, Fırat KÜÇÜK <firatkucuk at gmail.com>:
>> >> hi,
>> >>
>> >> for instance my treeparser rule is
>> >>
>> >>
>> >> sample_rule
>> >>     :   ^(SOME_TOKEN
>> >>             bla_bla_rule
>> >>             { if (1 == 1) { }
>> >>             another_rule_should_be_in_if_statement
>> >>             {  }  }
>> >>         )
>> >>      ;
>> >>
>> >>
>> >> "another_rule_should_be_in_if_statement" rule should be in "if (1==1)
>> >> {}" statement.
>> >> What should i do?
>> >>
>> >> --
>> >> Öğr. Gör. Fırat KÜÇÜK
>> >> ADAMYO Distance Learning
>> >> SAKARYA University / TURKEY
>> >>
>>

I suppose:

sample_rule
    :    SOME_TOKEN bla_bla_rule ({1 == 1}? another_rule)*
    ;

or

sample_rule
    :    SOME_TOKEN bla_bla_rule another_rule ({1 == 1}? another_rule)*
    ;

(a)* means: apply (a) zero or more times (kleene closure).
(a)? means: apply (a) zero or one time(s), i.e.: (a | empty)
(a)+  means (a) one or more times, i.e.: (a) (a)*
So I expected the last one to be equivalent to:

sample_rule
    :    SOME_TOKEN bla_bla_rule ({1 == 1}? another_rule)+
    ;

But it doesn't seem to work the same way.
Maybe someone can recommend a good tutorial.

Panayiotis