[antlr-interest] simple grammar with wildcard

[Shaoting Cai]

Hi Jason,

The fragment rule NONQUOTE hides the ID rule.
# is 35, ~ is 126
'a'..'z' and 'A'..'Z' is within 35..126

>  fragment
>  NONQUOTE
>    :' '..'!'|'#'..'~'|'\r'|'\n';

-Shaoting



On Wed, Apr 23, 2008 at 7:46 AM, jason zhang <jasonzhang2002 at gmail.com> wrote:
> Hi, All
>  I have a simple grammar. I can not get it work. Help is appreciated.
>  My input text is like this
>  name:"value". The value can span multiple line.
>  My grammar is like this
>  -------------------
>  grammar Test;
>  program : attribute*;
>  attribute : n=ID ':' '"' e=ATTRVALUE '"' LINEBREAK{
> System.out.println("match attrname==============="+$n.text+"
> attrvalue="+$e.text);};
>
>
>  ATTRVALUE:NONQUOTE*;
>  ID :('a'..'z'|'A'..'Z'|'0'..'9'|'-'|'_')+;
>  WS : ( '\t' | ' ' )+     { $channel = HIDDEN; } ;
>  LINEBREAK
>    :    '\r'?'\n';
>  //printable ASCII character except ", including \r and \n.
>  fragment
>  NONQUOTE
>    :' '..'!'|'#'..'~'|'\r'|'\n';
>  ---------------------
>  When I check this grammar through antlrWorks, I got the error like " The
> following token definitions are unreachable: ID,LINEBREAK".
>
>  -jason
>
>
>
>
>
>
>