[antlr-interest] Novice Question - Token for all characters from a given point to End of Line
Matt Palmer
mattpalms at gmail.com
Tue Aug 5 12:49:45 PDT 2008
Ooops! I guess so :)
Matt
On Tue, Aug 5, 2008 at 8:46 PM, Foust <javafoust at gmail.com> wrote:
> Ø (options{greedy=false;} : . ) NEW_LINE
>
>
>
> Did you mean:
>
>
>
> .*
>
> ?
>
>
>
> Brent
>
> *From:* antlr-interest-bounces at antlr.org [mailto:
> antlr-interest-bounces at antlr.org] *On Behalf Of *Matt Palmer
> *Sent:* Tuesday, August 05, 2008 11:22 AM
> *To:* Brisard, Fred D
> *Cc:* antlr-interest at antlr.org
> *Subject:* Re: [antlr-interest] Novice Question - Token for all characters
> from a given point to End of Line
>
>
>
> Hi Fred,
>
> You should be able to use predicates, something like this:
>
> COMMAND
> : 'create' | 'delete' { inCommand = true; }
> ;
>
> COMMAND_TOKEN
> : {inCommand}?=>
> (options{greedy=false;} : . ) NEW_LINE { inCommand = false; }
> ;
>
> Matt.
>
> On Tue, Aug 5, 2008 at 7:03 PM, Brisard, Fred D <Fred.Brisard at ca.com>
> wrote:
>
> I have a keyword style grammar and have the need to accept all the
> characters until the end of line to be accepted as a single token.
>
> For example, I have a statement that is of the following type
>
> Command multiple arguments (EOL)
>
> Where Command can be a command name and the multiple arguments are one or
> more arguments. There can be from 1 to many arguments – each argument
> does not have a fixed content – it may be an integer, a string, a quoted
> string. The characters in the string can be most anything.
>
> I was looking for something similar to the multiple line comment technique
> using the greedy=false option. Collect all the characters following the
> Command into a single token.
>
> Any ideas or suggestions are appreciated.
>
> Regards, Fred
>
>
>
-------------- next part --------------
An HTML attachment was scrubbed...
URL: http://www.antlr.org/pipermail/antlr-interest/attachments/20080805/4af81abb/attachment.html
More information about the antlr-interest
mailing list