[antlr-interest] How to define a FLOAT number
maulattu
maulattu at yahoo.it
Thu Feb 28 09:08:37 PST 2008
Hello, here is a little surprise..
With the following grammar, the input "1" is not recognized as float (note that the rule DIGIT isn't used):
------------------------------
grammar float_recon;
offset
:
FLOAT
;
DIGIT
: '0'..'9'
;
FLOAT
:
('0'..'9')+ ('.' (('0'..'9')+))?
;
------------------------------
Conversely, with this one the input "1" is recognized as float:
------------------------------
grammar float_recon;
offset
:
FLOAT
;
FLOAT
:
('0'..'9')+ ('.' (('0'..'9')+))?
;
DIGIT
: '0'..'9'
;
------------------------------
How can it be possible? Is it related to this bug?
http://www.antlr.org:8888/browse/ANTLR-41
I'm using ANTLRWorks 1.1.7 and 1.1.5 some days ago...
Bye!
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