[antlr-interest] exit status from "java antlr.Tool ,,,"
kaberdude at yahoo.com
kaberdude at yahoo.com
Thu Nov 15 17:26:40 PST 2001
I'm an off-on Antlr user. I'm trying to write a grammar for Dot
(ATT's Graphvis), appropriately massaged to be LL(k) (not easy!).
Anyways, after playing around, I noticed that it is not reliably
exiting with non-zero status when there is a severe problem in the
grammar. So, I tried this:
"java antlr.Tool y" where y contains exactly the character "y".
$ java antlr.Tool y
ANTLR Parser Generator Version 2.7.1 1989-2000 jGuru.com
y:1: unexpected token: y
y: error: rule grammar trapped: y:1: unexpected token: y
$ echo $?
0
This isn't a correct grammar, so it would be nice if the
tool would exit() with 1 (error) instead of 0 (ok).
Looking at the source, antlr.CharScanner defines reportError()
without a System.exit(1), but doesn't record if there was an error
for later regurgitation. However, a generated lexer for my
(corrected) grammar defines reportError() as:
public void reportError(String s) {
super.reportError(s);
System.exit(1);
}
which is slightly better.
Am I doing something wrong?
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