[antlr-interest] stuck expr
jagad
jagad at enciety.com
Wed Oct 1 07:25:17 PDT 2003
Hi Ric,
Yes, I call MyParser.expr() and No, I don't cut out, the whole result
it's just like I sent.
Here my snippet:
#include "parser/MyParserLexer.hpp"
#include "parser/MyParserParser.hpp"
#include <iostream>
#include <sstream>
int main()
{
ANTLR_USING_NAMESPACE(std)
ANTLR_USING_NAMESPACE(antlr)
try{
MyParserLexer lexer(cin);
MyParserParser parser(lexer);
parser.expr();
}
catch(exception& e){
cout << "exception: " << e.what() << endl;
}
return (0);
}
---------------
The snippet just like the ANTLR example :)
I have read the generated code (as adviced by Monty) and it's strange
that goal() not called at the first time. Could you give me info where
actually the first ANTLR C++ call ?
Best Regards
jagad
P.S: Is it possible that sleepless affecting my code? :) just joke,
ANTLR is great and your works at ANTLR C++ is great. Great Tools with a
newbie hand like me could be a problem :)
On Wed, 2003-10-01 at 20:57, Ric Klaren wrote:
> On Wed, Oct 01, 2003 at 09:05:07PM +0700, jagad wrote:
> > I use -parserTrace and try input:
> >
> > (1+2),(1+3);
> >
> > The Output:
> > ------------------------------------
> > > expr; LA(1)==(1+2),(1+3);
>
> Hmmm you are calling the goal rule I hope? And not MyParser.expr() ? Or did
> you cut out the traces for goal and exprList ?
>
> Cheers,
>
> Ric
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