[antlr-interest] stuck expr

[mzukowski at yci.com]

See that parser.expr()?  That's where you are calling the expr rule at the
top level.  Sounds like you really want to be calling parser.goal().

Good catch, Ric.

Monty

-----Original Message-----
From: jagad [mailto:jagad at enciety.com] 
Sent: Wednesday, October 01, 2003 7:25 AM
To: ANTLR Milis
Subject: Re: [antlr-interest] stuck expr

Hi Ric,

Yes, I call MyParser.expr() and No, I don't cut out, the whole result
it's just like I sent.

Here my snippet:

#include "parser/MyParserLexer.hpp"
#include "parser/MyParserParser.hpp"
#include <iostream>
#include <sstream>

int main()
{	
	ANTLR_USING_NAMESPACE(std)
	ANTLR_USING_NAMESPACE(antlr)
	
	try{		
		MyParserLexer lexer(cin); 
		MyParserParser parser(lexer);
	
		parser.expr();
	}
	catch(exception& e){
		cout << "exception: " << e.what() << endl;
	}
	
	return (0);
}

---------------

The snippet just like the ANTLR example :)
I have read the generated code (as adviced by Monty) and it's strange
that goal() not called at the first time. Could you give me info where
actually the first ANTLR C++ call ?

Best Regards

jagad

P.S: Is it possible that sleepless affecting my code? :) just joke,
ANTLR is great and your works at ANTLR C++ is great. Great Tools with a
newbie hand like me could be a problem :)


On Wed, 2003-10-01 at 20:57, Ric Klaren wrote:
> On Wed, Oct 01, 2003 at 09:05:07PM +0700, jagad wrote:
> > I use -parserTrace and try input:
> > 
> > (1+2),(1+3);
> > 
> > The Output:
> > ------------------------------------
> >  > expr; LA(1)==(1+2),(1+3);
> 
> Hmmm you are calling the goal rule I hope? And not MyParser.expr() ? Or
did
> you cut out the traces for goal and exprList ?
> 
> Cheers,
> 
> Ric


 

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