[antlr-interest] Tree transformation

Arnar Birgisson arnarb at oddi.is
Thu Oct 9 11:09:57 PDT 2003


Hello..

I get this:

g:\j2sdk1.4.2\bin\java -cp g:\jars\antlr.jar antlr.Tool
FjolnirTransformer.g
ANTLR Parser Generator   Version 2.7.3-20030430   1989-2003 jGuru.com
FjolnirTransformer.g:115:11: Suffixing a root node with '!' is not
implemented
Exiting due to errors.

I think I'm running the latest and greatest (2.7.3 from Ric, dated
2003-09-11).

Arnar



> -----Original Message-----
> From: mzukowski at yci.com [mailto:mzukowski at yci.com] 
> Sent: 9. október 2003 15:51
> To: antlr-interest at yahoogroups.com
> Subject: RE: [antlr-interest] Tree transformation
> 
> 
> Something like this should do the trick except for the EMPTY_LIST bit:
> 
> parent_expr : #(l:PARENT! s:stmt_list);
> 
> stmt_list : stmt {##=#([STATEMENT_LIST],##);} (stmt_list)? ;
> 
> Try this for EMPTY_LIST functionality, but it probably needs some more
> thinking about if you get ambiguity warnings:
> 
> stmt_list : stmt {##=#([STATEMENT_LIST],##);} 
>            (stmt_list
> 		| /*empty*/ {##=#(null,##,EMPTY_LIST);}
> 		) 
> 
> ;
> 
> Note that #(null,a,b) builds a list A B with no root (null is 
> the root--get
> it?)
> 
> Monty
> 
> -----Original Message-----
> From: Arnar Birgisson [mailto:arnarb at oddi.is] 
> Sent: Thursday, October 09, 2003 4:44 AM
> To: antlr-interest at yahoogroups.com
> Subject: RE: [antlr-interest] Tree transformation
> 
> Hello..
> 
> Thanks, but what I need is a bit more. I need a more general method of
> converting a list like structure like
> 
> PARENT
>  |
> C1 - C2 - C3 - ... - CN
> 
> to a right-balanced tree like this:
> 
> FUNC
>  |
> C1 - FUNC
>       |
>      C2 - FUNC
>            |
>           C3 - FUNC
>                 |
>                 ... 
>                    C(N-1) - FUNC
>                              |
>                              CN - EMPTY_LIST
> 
> What I am implementing is basically the conversion from
> "[expr1,expr2,...,exprN]" to a lisp-like list, which is equivalent to
> "expr1 : (expr2 : (expr3 : ... (exprN : []) ... ))", where ":" is like
> the "cons" operator in lisp, and "[]" is a lexical constant 
> representing
> the nil list.
> 
> I thought of writing a function that takes three ASTs, one like this
> #(FUNC), one #(EMPTY_LIST) and the third one like #(LIST 
> node1 node2 ...
> nodeN), and returns an AST like this: #(FUNC node1 #(FUNC node2 #(...
> #(FUNC nodeN EMPTY_LIST) ...) ) ). I will try this and let you know.
> 
> Hope that explains it..
> 
> Arnar
>                                         
> 
> > -----Original Message-----
> > From: mzukowski at yci.com [mailto:mzukowski at yci.com] 
> > Sent: 8. október 2003 22:19
> > To: antlr-interest at yahoogroups.com
> > Subject: RE: [antlr-interest] Tree transformation
> > 
> > 
> > Ack, the formatting got blarked.  Should be this:
> > 
> > list_expr! : #(l:LIST s:stmt_list) {##=#(#[LPAREN,")"], 
> > #[NAME,"func"], s);}
> > 
> > stmt_list : #(STATEMENT_LIST (stmt)*)
> > 
> > -----Original Message-----
> > From: mzukowski at yci.com [mailto:mzukowski at yci.com] 
> > Sent: Wednesday, October 08, 2003 3:11 PM
> > To: antlr-interest at yahoogroups.com
> > Subject: RE: [antlr-interest] Tree transformation
> > 
> > Your description is a bit unclear, but to get this:
> > 
> > LPAREN
> >  |
> > NAME("func") - STATEMENT_LIST 
> >                 |
> >                ID(a) - ID(b) - ID(c)
> > 
> > Do this:
> > 
> > list_expr! : #(l:LIST s:stmt_list) {##=#(#[LPAREN,")"], 
> > #[NAME,"func"], s);}
> > stmt_list : #(STATEMENT_LIST (stmt)*)
> > 
> > Monty
> > 
> > -----Original Message-----
> > From: Arnar Birgisson [mailto:arnarb at oddi.is] 
> > Sent: Wednesday, October 08, 2003 12:03 PM
> > To: antlr-interest at yahoogroups.com
> > Subject: [antlr-interest] Tree transformation
> > 
> > Hello..
> > 
> > I have a programming construct "[a,b,c]" which defines a 
> list (in the
> > lisp sense) of the results of expressions a, b and c. The 
> > parser returns
> > this tree: #([LIST,"["], #(STATEMENT_LIST, #a, #b, #c)). I.e.
> > 
> > LIST
> >  |
> > STATEMENT_LIST
> >  |
> >  ID - ID - ID
> > 
> > My languages sematnics define "[a,b,c]" to be eqivalent
> > "func(;a,func(;b,c))", and moreover, the user program might define
> > "func" to be whatever function the user wants it to be.
> > 
> > (As a side note: the function call syntax in the language is
> > func(x1,..,xN;y1,..,yM) where x1,..,xN are copy-in copy-out 
> > parameters,
> > and y1,...,yM are pass-by-value. Also, there is no 
> distinction between
> > statements and expressions.)
> > 
> > I have one tree parser that takes the parser output and 
> simplifies the
> > tree, before that is passed to another tree-parser, the code 
> > generator.
> > 
> > The simplifying treeparser (the transformer) does things 
> like convert
> > "expr1 + expr1" to "+(;expr1,expr2)", and I furthermore want it to
> > convert the tree for "[a,b,c]" to the tree 
> "func(;a,func(;b,c))" would
> > have generated.
> > 
> > In a nutshell, I need to convert trees of the form depicted 
> above, to
> > this:
> > 
> > LPAREN
> >  |
> > NAME("func") - STATEMENT_LIST - STATEMENT_list
> >                                  |
> >                                  ID(a) - ID(b) - ID(c)
> > 
> > How would you do in a tree-parser rule? The rules I have to 
> match the
> > input tree are:
> > 
> > list_expr : #(LIST stmt_list)
> > stmt_list : #(STATEMENT_LIST (stmt)*)
> > 
> > Arnar
> > 
> > ps. for the sake of completeness, the actual language doesn't 
> > use "func"
> > as the function name, but rather ":". Operatrs in the language are
> > simply functions as the equivalence "a+b"="+(;a,b)" implied.
> > 
> > 
> >  
> > 
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